Question

$\huge\red{Question:}$

Draw a line segment AB of length 7 cm and find a point P on it such that AP:PB = 1:3
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Answer 1

Answer :

The measure of AP and PB are $\dfrac{7}{4}$ cm and $\dfrac{21}{4}$ cm respectively.

See the explanation!

Step-by-step explanation :

Given that :

• The length of AB is 7cm.

• AP : PB => 1:3.

To Do :

We have to measure AP : PB. and drawline segment AB of length 7 cm and find a point P on it such that AP : PB = 1 : 3.

Solution :

★ Measuring :

$\bigstar\;\textbf{\underline{\underline{Consider as -}}}$

The measure of AP and PB as - x & y.

So,

$\sf \implies AB=AP+PB\\ \\\implies 7=x+y\\ \\\implies 7 = 4x\\ \\\implies x = \dfrac{7}{4}$

Measure of AP and PB are :

$\sf \implies AP = x =\dfrac{7}{4}\\ \\\implies PB=y=3\times \dfrac{7}{4}=\dfrac{21}{4}\\ \\ \\\bigstar \textbf{\underline{\underline{The measure of AP and PB are 7/4 cm and 21/4 cm respectively.}}}$

$\rule{300}{1.5}$

★ Construction :

⇒ Draw a line segment AB = 7cm  

⇒ Take ∠A8, AB = ∠AB, B8.

⇒ (3 + 5) = 8 then, Mark A1, A2 etc.....

⇒ Join A , B8 and A2, B7 similarly all points.........

⇒ Point of intersection of A3, B5 & AB is point P.

★ Refer to the Attachment for Figure.

Answer 2

SOLUTION ⬆️

Refer to the attachment.

Hope it helps ☺️