Math, asked by nehu215, 10 months ago

\huge\red{questiOn}

Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

no useless answers

Answers

Answered by abhi52329
1

Answer:

Cost are $1 and $1.5

Step-by-step explanation:

Let the cost of pipe sold on profit be x

Let the cost of pipe sold on loss be y

Given

1.20 = x \times 1.2

x =   \frac{1.2}{1.2}  = 1

Also

1.20 = y \times .8

y =  \frac{1.2}{.8}  = 1.5

Answered by Anonymous
5

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\huge\red{\underline{{\bf Question : }}}

  • Mr. Jones sold two pipes at Rs. 1.20 each. Based on the cost his profit on one was 20% and his loss on the other was 20%. On the sale of the pipes, he :

\huge\red{\underline{{\bf Answer : }}}

 \large\bf{\underline\blue{Solution:-}}

  • For 1st pipes,

  • SP (selling price) = 1.20

  • Profit = 20%

\large{\boxed{{\bf\pink{CP\: = SP\: - \: profit. }}}}

\sf\green{⟼CP = 1.20 - 20\% \times CP}

 \sf\green{⟼120\%CP =1. 20}

\sf\green{⟼CP =  \frac{1.20}{120}  \times 100}

\sf\green{⟼CP _{1}  = 1.00}

\large{\boxed{{\bf\pink{ For\: 2nd=s.p + loss}}}}

 \sf\green{⟼CP  = 1.20 + 200\%CP}

\sf\green{⟼80\%CP = 1.20}

 \sf\green{⟼CP=\frac{1.20}{80}\times 100 = 1.50}

 \sf\green{⟼Total\:CP = 1.00+1.50 = 2.50}

 \sf\green{⟼Total\:SP = 1.20 + 1.20 = 2.40 }

  • He suffered 10 paise loss.

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