Question

$\huge \red{question}$
The square of the greater of two consecutive even number exceeds the square of the smaller by 36. Find the numbers. ​

Answer 1

Answer:

Let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8

$\huge \green{ \boxed{ x = 8}}$

Answer 2

Answer:

$\huge \red{copy.. answer}$

Step-by-step explanation:

Let the nos be x and (x+2) becuz they are consecutive even nos .

so:(x+2)2 -x2 =36

(x+2+x)(x+2-x)=36

(2x+2)(2)=36

2x+2=18

2x=16

x=8

{ x = 8}}

x=8