Question

$\huge\red{Question}$

The value of a property decrease every year at the rate of 5%. If its present value Rs. 4,11,540, what was its value three years ago.



​

Answer 1

Answer:

present value = Rs 411540

rate of depreciation = 5% p.a

time(n) = 3 years

value 3 yrs  ago = $p-( 1 - \frac{R}{100} )^{n}$

$4,11,540 =p( 1 - \frac{5}{100} )^{3}$

on further solving

$4,11,540 =p( \frac{19}{20} )^{3}$

$4,11,540 =p( \frac{6859}{8000} )$

on multiplying RHS by $( \frac{6859}{8000} )$ and dividing LHS by $( \frac{6859}{8000} )$

We get final answer ₹480000

Answer 2

Answer:

A] present value = Rs 411540

rate of depreciation = 5% p.a

t = 3 years

value 3 yrs ago=p(1−

100

R

)

n

⇒411540=p(1−

100

5

)

3

⇒411540=p(

100

95

)

3

⇒411540=p(

20

19

)

3

⇒411540=p(

8000

6859

)

3

⇒

6859

411540×80000

=Rs480000