Question

$\huge\red{Question}$


The value of a property decrease every year at the rate of 5%. If its present value Rs. 4,11,540, what was its value three years ago .​

Answer 1

ANSWER is :- 480000rs.

solved by the formula of compound interest

for further information please check in attachment

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Answer 2

Solution:

Given :

• Value = Rs. 411540

• Rate = 5%

• Time = 3 years

To find :

• It's value after three years.

★ Formula used :

$\bold {p(1 - \frac{r}{100} {)}^{n} }$

So,

$\bold {411540= p(1 - \frac{5}{100} {)}^{3} } \\ \\ \bold {411540 = p( \frac{95}{100} {)}^{3} \: \: \: \: \: \: \: \: } \\ \\ \bold{411540 = p( \frac{19}{20} {)}^{3} } \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{411540 =p( \frac{6859}{8000 } {)}^{3} } \\ \\ \bold{ \frac{411540 \times 8000}{6859} = rs.480000}$