Question

$\huge\red{Question}$


The value of a property decrease every year at the rate of 5%. If its present value Rs. 4,11,540, what was its value three years ago .


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Answer 1

Step-by-step explanation:

I hope its help full to you

Answer 2

Value of property before 3 years = $\boxed{ \bf\red{480000 \: RS} }$

$\underline{\underline{ \sf Given :- }}$

• Value of property decreases at rate of 5%

• Present value is 4,11,540 RS

$\underline{\underline{ \sf To \: Find:- }}$

• Value before 3 years

$\huge\underline{\underline{ \sf Formula \: - }}$

• $\boxed{ \sf \red{ A = P\bigg( 1 + \frac{r}{100} \bigg) ^{ n} }}$

• A = Amount

• P = principal amount

• r = rate

• n = number of years

$\huge\underline{\underline{ \sf Answer :- }}$

To Find value 3 years ago ,

• $\boxed{ \sf \red{ A = P\bigg( 1 - \frac{r}{100} \bigg) ^{ n} }}$

$\bigg($ $\sf \frac{-r}{100}$ indicates value before the year $\bigg)$

• A = 4,11,540 RS

• n = 3

• r = 5

Substituting the values ,

• $\sf4 11540 = p \bigg(1 - \frac{5}{100} \bigg) {}^{3}$

• $\sf411540 = p \bigg({ \frac{95}{100} \bigg) }^{3}$

• $\sf411540 =p \bigg( {\frac{19}{20} } \bigg)^{3}$

• $\sf411540 = p \bigg( \frac{6859}{8000} \bigg)$

• $\sf \: p = 411540 \times \frac{8000}{6859}$

• $\sf \: p = 480000$

$\rule{10cm}{0.005cm}$

Value of property before 3 years = 480000 RS

$\rule{10cm}{0.002cm}$