Math, asked by StunningBabe27, 11 months ago

{\huge{\red{\underline{\bold{QuestioN↑}}}}}

ʙᴏᴀʀᴅ- ɪᴄsᴇ 10
______________
• sᴏʟᴜᴛɪᴏɴ sʜᴏᴜʟᴅ ʙᴇ ᴄʟᴇᴀʀ ᴀɴᴅ ɪᴛ ɪs ᴀʙʟᴇ ᴛᴏ ᴜɴᴅᴇʀsᴛᴀɴᴅ.

• ɴᴏ ғᴀʟᴛᴜ ᴀɴsᴡᴇʀs ᴛᴏ ʙᴇ ɢɪᴠᴇɴ.

• ᴄᴏʀʀᴇᴄᴛ sᴏʟᴜᴛɪᴏɴ ᴡɪʟʟ ʙᴇ ᴍᴀʀᴋ ʙʀᴀɪɴʟɪᴇsᴛ ᴀɴᴅ 50 ᴛʜᴀɴᴋs ᴛᴏ ʜɪs/ʜᴇʀ ᴀɴsᴡᴇʀs.​

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Answers

Answered by kausalya61
3

= sin2 34˚ + cos2 (90˚ – 56˚) + 2 tan 18˚ cot(90˚ – 72˚) – (√3)2

= (sin2 34˚ + cos2 34˚) + 2 tan 18˚ × 1/tan 18˚ – 3

= 1 + 2 – 3 = 3 – 3 = 0

Answered by Anonymous
8

 \bf{  \orange{ ={ \sin}^{2} 34 \degree + { \sin}^{2} 34 \degree + 2 \tan18 \degree \tan72 \degree -   { \cot}^{2} 30 \degree }}

  \bf{\pink {={ \sin }^{2}34 + [ \sin(90 \degree - 34 \degree ]  {}^{2} + 2 \tan18 \degree \tan(90 \degree - 18 \degree) -  { \cot}^{2}  30  \degree }}

   \bf{ \red{= { \sin }^{2} 34 +  { \cos}^{2}34 \degree + 2 \tan18 \degree \cot18 \degree -  ({ \sqrt{3}) }^{2}    }}

 \bf{ \green{ = 1 + 2 \tan18 \degree \times  \frac{1}{ \tan18 \degree }  - 3 }}

 \bf{ \purple{ = 1 + 2   \: \cancel{\tan18 \degree} \times  \frac{1}{  \cancel{ \tan18 \degree }}  - 3 }}

 \bf{ \blue{ = 1 + 2 - 3 = 0}}

 \bf{hence \: value \: is \:  \red0.}

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