Question

${\huge {\red {\underline {\underline {\mathcal {♡QuEstioN♡⤵}}}}}}$
$\: \: \: \: \:$
If arg (z – 1) = arg (z + 3i), then find (x – 1) : y, where z = x + iy.
$\: \: \:$
⚠️ Don't Spam ⚠️​

Answer 1

$\huge \mathbb{ \red {★᭄ꦿ᭄An} \pink{s}\purple{S} \blue {w} \orange{e} \green{R★᭄ꦿ᭄}}$

We have arg (z – 1) = arg (z + 3i), where z = x + iy

=> arg (x + iy – 1) = arg (x + iy + 3i)

=> arg (x – 1 + iy) = arg [x + i(y + 3)]

Hope it's helps..

Answer 2

Answer:

${\huge{\underbrace{\overbrace{\color{aqua}{Answer♡}}}}}$

We have arg (z – 1) = arg (z + 3i), where z = x + iy

=> arg (x + iy – 1) = arg (x + iy + 3i)

=> arg (x – 1 + iy) = arg [x + i(y + 3)]

hope this helps

ab apne mera naam thik likha