Question

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Determine the equation of the circle with radius 4 and Centre (-2, 3).
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Answer 1

Given that:

• Radius, r = 4, and center (h, k) = (-2, 3).

• We know that the equation of a circle with centre (h, k) and radius r is given as

$→ (x – h)² + (y – k)² = r² \: \: \: ….(1)$

• Now, substitute the radius and center values in (1), we get

• Therefore, the equation of the circle is

$→ (x + 2)²+ (y – 3)² = (4)²$

$→ x²+ 4x + 4 + y² – 6y + 9 = 16$

• Now, simplify the above equation, we get:

$→ x² + y²+ 4x – 6y – 3 = 0$

• Thus, the equation of a circle with center (-2, 3) and radius 4 is :

$→ x² + y²+ 4x – 6y – 3 = 0$

Answer 2

Explanation:

Given the centre of the circle is (−3,2) and radius is 4.

Given the centre of the circle is (−3,2) and radius is 4.Let (x,y) be any point on the circle now the equation of the circle is

Given the centre of the circle is (−3,2) and radius is 4.Let (x,y) be any point on the circle now the equation of the circle is (x+3)) 2

Given the centre of the circle is (−3,2) and radius is 4.Let (x,y) be any point on the circle now the equation of the circle is (x+3) 2 +(y−2) 2 =4

Given the centre of the circle is (−3,2) and radius is 4.Let (x,y) be any point on the circle now the equation of the circle is (x+3) 2 +(y−2) 2 =4 2 .