Question

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☆ What is →

$\pink\star\mapsto \: \bf{angular \: displacement} \\ \\ \pink\star \mapsto \: \bf{angular \: velocity} \\ \\ \red\star \mapsto \: \bf{angular \: acceleration} \\ \\ \red\star \mapsto \bf {angular \: momentum}$
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Answer 1

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$\green{\star\leadsto} \: \bf{Angular \: Displacement (\theta)}$

★ It is the Angle described by the position of vector r about the Axis of rotation

$\pink{ \star \leadsto} \bf{</em><em>A</em><em>ngular \: </em><em>V</em><em>elocity (\omega)}$

★ It is the rate at which Angular displacement changes with time i.e.

$\longrightarrow\omega \: = \frac{d \theta}{dt}$

$\blue{ \star \leadsto} \bf{</em><em>A</em><em>ngular \: </em><em>A</em><em>cceleration( \alpha )}$

It is the rate of change of Angular velocity of body about the given axis of rotation i.e.

$\longrightarrow \alpha = \frac{d \omega}{dt}$

$\red{ \star \leadsto} \bf{</em><em>A</em><em>ngular \: </em><em>M</em><em>omentum \: (l )}$

It is the product of linear momentum and perpendicular distance of line of action of linear momentum vector from the Axis of rotation .

Answer 2

★ It is the Angle described by the position of vector r about the Axis of rotation

★ It is the rate at which Angular displacement changes with time i.e.

★It is the rate of change of Angular velocity of body about the given axis of rotation i.e.

★It is the product of linear momentum and perpendicular distance of line of action of linear momentum vector from the Axis of rotation .