Question

$\huge\rm{{Question}}$
To make a saturated solution 36 g of sodium chloride is dissolve in 100 g of water at 293 k . find its concentration at this temperature.

Class : 9th
Subject : Science
Chapter : Is matter Around Us Pure. ​

Answer 1

$\small{{{ \boxed{ \boxed{ \begin{array}{cc} \bf \to \: given : \\ \\ \sf \hookrightarrow \: mass \: of \: solvent(water) \: \: = 100 \: g \\ \\ \sf \hookrightarrow \: mass \: of \: solute({NaCl}) = 36 \: g \\ \\ \blue{\bf \: we \: have \: to \: find : } \\ \\ \sf \hookrightarrow \: concentration \: of \: the \: solution \: = C \\ \\ \\\red{ \underline{ \bf{solution}}} \\ \\ \\ \boxed{ \mapsto \sf \: solution \: = solvent + solute} \\ \\ \small{\mapsto \sf \: mass \: of \: the \: solution \: = 100 + 36 = 136 \: g} \\ \\ \\ \pink{ \sf \: we \: know \: that : } \\ \\ \text{concentration(C) = } \frac{ \text{mass \: of \: solute}}{ \text{mass \: of \: solution}} \\ \\ \rm \: \implies \: C = \frac{36}{136} \\ \\ \rm \implies \: C= 0.264 \: M \\ \\ \\ \rm \: concentration \: in \: percentages : \\ \\ \rm \: C = 0.264 \times 100 \: \% \: = 26.4 \: \% \: \\ \\ \\ \\ \small{\green{ \boxed{ \sf \: concentration \: of \: the \: solution \: C = 0.264M \: or \: 26.4 \%}}}\\ \\ \end{array}}}}}}$

Answer 2

$\\ \large\frak{Given} \begin{cases} \bullet \quad \sf mass \: of \: solute = 36g \\ \bullet \quad \sf mass \: of \: solvent = 100g \end{cases}$

We are asked to find the concentration at this temperature. So, for that We know, Solution is the mixture of Solute as well as solvent. Hence, Mass of Solution will be = 36 + 100 = 136g

$\\ \leadsto \underline{ \boxed{ \sf concentration = \frac{mass \: of \: solute}{ mass \: of \: solution} }} \bigstar$

Calculation:-

$\\ \quad : \implies \sf concentration = \frac{36}{136}$

$\\ \quad \therefore \boxed{ \boxed{\sf concentration = 0.264 M}} \bigstar$

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