Question

$\huge \sf \blue {\underline { \underline { \sf Question :- }}}$


Q. Find the compound interest on ₹160,000 for 2 years at 10% per annum when Compounded semi - annually. ​

Answer 1

$\huge\bold\red {ANSWER}$

$\huge\sf\purple {\underline {\sf ☆Given :-}}$

Principal (P) = Rs 1,60,000

Rate (R) = 10% per annum

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{10}{2}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5\% \: per \: half \: year$

Time (t) = 2 years

= 2×2

= 4 half years

$\huge\sf\orange {\underline {\sf ☆To\:find :-}}$

Compound Interest =???

$\huge\sf\green {\underline {\sf ☆Solution :-}}$

$compound \: interest = p(( { \frac{1 + r}{10} }))^{n - 1}$

$\: \: \: \: \: \: \: \: \: \: = 160000 { (\frac{1 + 5}{100} })^{4 - 1}$

$\: \: \: \: \: \: \: \: \: \: \: \: = 160000 (\frac{194481}{160000 - 1} )$

$\: \: \: \: \: \: \: \: \: \: \: \: = \frac{160000 \times 34481}{160000}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: = rs \: \: 34481$

$\huge\mathcal {Hope\:It\:Helps\:You}$

Answer 2

Step-by-step explanation:

34481 is the answer of this question

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