Question

$\huge \sf \color{purple}\colorbox{red}{ }$

can anyone pls solve this​

Answer 1

Each year no.of . sheeps increases by 8%

so ,

$\sf1 st \: \: \: year =( \frac{8}{100} \times 200 )+ 200 \\ \\ \sf = 16 + 200 = 216 \: \: sheeps$

• 1 st year = 216 sheeps

$\sf 2nd \: \: year = 2( \frac{8}{100} \times 200) + 200 \\ \\ \sf = 32 + 200 = 232 \: \: sheeps$

• 2nd year = 232 sheeps

$\sf3rd \: \: year \: \: = 3( \frac{8}{100} \times 200) + 200 \\ \\ \sf = 48 + 200 = 248 \: \: sheeps$

• 3rd year = 248 sheeps

$\red{ \mathfrak{hope \: \: \: \: this \: \: \: will \: \: \: help \: \: \: you}}$

Answer 2

Answer:

$\bold \color{black}SOLUTION:-$

Here, P = Present number of sheep's = 200

R = Increase in number of sheep's per

years%

N = 3 yrs

$\sf \: A=P(1+ \frac{R}{100})n \\ \\ \sf \: 200(1 + \frac{8}{100} )3 \\ \\ \sf \:200( \frac{100 + 8}{100} )3 \\ \\ \sf \: 200( \frac{108}{100} ) \: \: \: \frac{27}{25} \\ \\ \sf \: 200 ( \frac{27}{25} )3 \\ \\ \sf \:200 \times \frac{27}{25} \times \frac{27}{25} \times \frac{27}{25} \\ \\ \sf \: 8 \times 27 \times \frac{27}{25} \times \frac{27}{25}$

$\sf= 251.9424 \\ \\ \sf= 252$

$\sf { \therefore}The \: \: number \: \: of \: \: sheep's \\ \sf \: \: with \: \: the \: \: \\ \: \: \sf \: sheeperd \: \: after \: \: \\ \sf \: \: 2 \: \: years \: \: would \: \: be \: \: 252 \: \: sheep's.$