Question

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$☆ What \: is \: Hybridisation ?$
Write the state of hybridisation of Sulphur in
$so \frac{}{2}$
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Answer 1

Answer:

In sulphur dioxide, the hybridization that takes place is sp2 type. To determine this, we will first look at the sulphur atom which will be the central atom. During the formation of SO2, this central atom is bonded with two oxygen atoms and their structure can be represented as O=S=O. As for the bonding, there is one sigma and one pi bond formed between sulphur and the two oxygen atoms. The atom will also accommodate one lone pair.



Let us break it down further. Looking at the ground state of sulphur consists of six electrons in the outermost shell and the first two shells are also completely filled. There are 4 electrons in the 3p portal and two paired electrons in the 3s orbital. Now, it has to form four bonds (with oxygen) and thus needs 4 unpaired electrons. This leads to the development of the excited state in sulphur where one 3px electron jumps to the 3d orbital. When this happens there will be one unpaired electron in one 3d orbital and three in 3p orbitals. However, the electrons that form the sigma bonds and the lone pair are at different energy levels. The stable state is obtained when hybridization takes place.

During hybridization, two 3p orbitals and one 3s orbital get hybridized. In total, there is a formation of three sp2 hybrid orbitals. In this, two hybrid orbitals contain unpaired electrons and one hybrid orbital will have the lone pair. These unpaired electrons then form sigma bonds with the oxygen atoms. Meanwhile, the 3d and 3p orbitals remain the same, and they take part in the formation of pi bonds.

Interestingly, the hybridization of the oxygen atom in this compound is also sp2

HOPE ITS HELPFUL ARMY...

Answer 2

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Hybridisation (or hybridization) is a process of mathematically combining two or more atomic orbitals from the same atom to form an entirely new orbital different from its components and hence being called as a hybrid orbital.

In sulphur dioxide (SO2), the hybridization type that takes place is sp2. To describe this, let us first look at the sulphur atom, which will be the SO2 hybridization of the central atom. At the time of SO2 formation, this central atom is bonded with two oxygen atoms, and their structure can be given as O=S=O.