Question

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A bag contains Rs.1 coins and
and Rs.2 coins whose total value is Rs.70. If the number of Rs.1 coin is five times that of Rs.2 coins,find the number of coins of each type.
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Answer 1

Solution:-

₹1 coins are =5×x = 5x. x= 10. The total amount of ₹ 1 coins the bag contains is 5×10=50. Hence ,the contains a total amount of ₹ 60( ₹50 + ₹10 = ₹60 ).

Answer:- ₹60

Answer 2

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A bag contains Rs.1 coins and Rs.2 coins whose total value is Rs.70. If the number of Rs.1 coin is five times that of Rs.2 coins,find the number of coins of each type.

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Let the number of Rs.2 coins be x.

As the number of Rs.1 coins are 5 times the number of Rs.1 coins are = 5×x = 5x.

Total number of Rs.1 coins are

${= 5x×1 =5x}$

Total number of Rs.2 coins are

$= 2 \times x = 2x$

According to the Question:⤵

$5x + 2x = 70$

$so, \: 7x = 70$

$\therefore \: x = 70 \div 7$

$x = 10$

Hence the total number of Rs. 2 coins contained in the bag is 10.

Total amount of Rs. 1 coins the bag contains is:

${5×10=50}$

Hence the bag contain the total number of

${60 \: coins \: (10 + 50 \: coins= 60 \: coins) }$

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