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Determine the range of
(x² + x + 1)/(x² - x + 1)
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Answers
Answered by
7
Answer:
Let y = (x²+x+1)/(x²−x+1)
⇒yx²-yx+y=x²+x+1
⇒(x−1)x²+(y+1)x+(y−1)=0
If x∈R, then
Discriminant ≥0
⇒(y+1)²−4(y−1)² ≥ 0
⇒−3y²+10y−3 ≥ 0
⇒3y²−10y+3 ≤ 0
⇒(3y−1)(y−3) ≤ 0
⇒31 ≤ y ≤ 3
∴ Range =[1/3,3]
Explanation:
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Answered by
7
So, The Range of ( x²+ x + 1 ) / ( x² - x + 1 ) is [ 1/3 , 3 ]
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