Question

$\huge{ \sf{ \green{ \underline{ \overline{ \underline{ \overline{ \pink{ \: Question \: : - }}}}}}}}$
The sum of three numbers in G.P . is 14. If the first two terms are each increased by 1 and the third term is decreased by 1 , the resulting numbers are in A.P . Find the product of these three numbers.
a) 125
b) 64
c) 216
d) 124​

Answer 1

Answer:

answer is below

hope I helped you

Step-by-step explanation:

Let the numbers be a,ar,ar

2

∴Sum=a(1+r+r

2

)=14...(1) Also

a+1,ar+1,4ar

2

−1 are in A.P

⇒a(r

2

−2r+1)=2..(2)

Divide (1) and (2) and simplifying

2r

2

−5r+2=0∴r=2,

2

1

and hence a=2,8

∴ Numbers are 2,4,8 or 8,4,2

The required difference of =6

Answer 2

$\huge{ \sf{ \green{ \underline{ \overline{ \underline{ \overline{ \pink{ \: Answer \: : - }}}}}}}}$
option c