D is a point on side BC of ΔABC such that ∠ABC > ∠ACB and AB > AD. Then, which of the following statement is always true?
A)∠ACB > ∠ADC
B)∠ABC > ∠AD
C)∠ACB < ∠ADC
D)∠ADB < ∠ABC
Answers
Answered by
0
i think c is answer
hope it's helps you
Answered by
1
In △ADC and △BAC
∠ADC=∠BAC (Given)
∠C is Common
∴ by AA Criterion of Similarity, △ADC ∼ △BAC⇒BA
AD
=
AC
DC
=
BC
AC
⇒
AC
DC
=
BC
AC
∴ CA
2
=CB.CD
hope it is helpful
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