Question

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How many terms of an A.P 1,4,7... are needed to give the sum 2380?
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Answer 1

Answer:

answer 40

Step-by-step explanation:

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Answer 2

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$s_{n} = \frac{n}{2} (2a + (n - 1)d) \\ 2380= \frac{n}{2} (2 \times 1 + (n - 1) \times 3) \\ 2380 \times 2 = n(3n - 1) \\ 4760 = n \: and \: 4760 = 3n - 1$

$n = 4760 \: or \: 1880.9...$

so,there are total of 4760 terms (1880.9.. is rejected as it is a decimal form.)