Question

$\Huge\sf\red{Hola\:!!!}$
What is the volume of $\sf\orange{ H_{2}}$ at STP is required to reduce 0.795 g of $\sf\pink{ CuO}$ to give $\sf\purple{ Cu}$ and $\sf\green{ H_{2}O}$ ?​

Answer 1

Answer:

not know

Explanation:

not know make me brain list

Answer 2

QUESTION -

What is the volume of $\sf\orange{ H_{2}}$ at STP is required to reduce 0.795 g of $\sf\pink{ CuO}$ to give $\sf\purple{ Cu}$ and $\sf\green{ H_{2}O}$ ?

SOLUTION -

GIVEN -

Mass of CuO , Cu = 0.795 g

Now ,

CuO + $\sf{ H_{2}}$ ----> Cu (S) + $\sf</p><p>{ H_{2}}$

79.5 g ------------ 22.4 lit

0.795 g ----------- ? ( x )

Now ,

→$\tt\dfrac{x}{22.4 \: lit} = \dfrac{0.795 \: g}{79.5 \: g}$

→$\tt x = \dfrac{0.795 \times 22.4 \: lit}{79.5}$

→ 0.224 lit

→ 224 ml

HENCE -

Volume of $\sf { H_{2}O}$ required = 224 ml