Question

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Two rods , 'A' and 'B', of same weight and equal length, have different thicknesses. A boy, while playing with them on a beach, held them vertically on the surface of sand as shown in the figure. Which one of them will sink less ? Explain.


please answer this one ⬆️⬆️ it's important.....

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Answer 1

Answer:-

Rod B will sink less.

Explanation:-

We know that:-

=>Pressure= Force/Contact area

∴Pressure ∝ 1/Contact area

∴Pressure ∝ Force

Pressure varies directly with thrust/force and inversely with contact area. This means more area will result in less pressure and less area will result in more pressure. Hence rod A will sink more as it's contact area is less and rod B will sink less as it's contact area is more.

Some Extra Information:-

Pressure:-

•Pressure is defined as the force per unit area.

•Pressure=Force/Contact area

•Pressure ∝ Force

Pressure ∝1/Contact area

•The S.I. unit of pressure is pascal or N/m².

•When a force of 1N is acting on an area of

1m²,then it is called 1 pascal.

Answer 2

Hello !

knowledge required:-

the object having less area of cross-section will penetrate more and the object having more area of cross section will penetrate least

here, we can observe that Rod A is thinner (i.e it has less area of cross section) hence, it will penetrate more/ sink more.

But, rod B is thicker (i.e. it has larger area of cross section) hence, it will penetrate less/ sink less.

So, our answer is Rod B