Question

$\huge\sf\underline{Question:-}$

Q} If ∆ABC is right angled at C, then the value of cos(A+B) is

(a) 0

(b) 1

(c) 1/2

(d) √3/2

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Answer 1

Answer:

Since ABC is a right angled triangle right angled at C

Hence

A+B=180 ⁰ −C=90 ⁰

Hence cos(A+B)

=cos(90 ⁰)

=0

Step-by-step explanation:

Answerd by #Madam divya ✌️

Answer 2

Answer:

Since ABC is a right angled triangle right angled at C

Hence

A+B=1800−C=900

Hence

cos(A+B)

=cos(900)

=0

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