Question

$\huge\star\pink{fx}$=

$\huge\star\pink{x^2-25÷x+5}$

where x not equal to -4​

find the value

Answer 1

Step-by-step explanation:

$({x}^{2} - 25) \div (x + 5) \\ = \frac{(x + 5)(x - 5)}{(x + 5) } \\ = (x - 5)$

$x -5 = 0 \\x = 5$

Answer 2

Answer:

x

2

−25)÷(x+5)

=

(x+5)

(x+5)(x−5)

=(x−5)

\begin{gathered}x -5 = 0 \\x = 5\end{gathered}

x−5=0

x=5