Question

$\huge{\star}{\underline{\boxed{\red{\sf{Question :}}}}}{\star}$

 cube of side 3 units has one vertex at one point (1,1,1) and the three edges from this vertex are respectively parallel to positive x-axis and negative y and z-axes. Find the coordinates of other vertices of the cube.

===================

No Spam! ​

Answer 1

Answer:

Coordinates of other points are:-

(4,1,1)

(1,-2,1)

(1,1,-2)

(4,-2,1)

(1,-2,-2)

(4,1,-2)

(4,-2,-2)

Step-by-step explanation:

Let us assume that the cube of 3 unit side length is drawn with vertex at (0,0,0) and vertices also on -ve y and -ve z axes.

So

The coordinates of the edges of the cube becomes :-

(0,0,0)

(3,0,0)

(0,-3,0)

(0,0,-3)

(3,-3,0)

(0,-3,-3)

(3,0,-3)

(3,-3,-3)

Suppose of vertex of a line is at (0, 0) and (4, 0)

If the entire is shifted parallely and the vertex of (0, 0) now lies at (x,y)

SO,

vertex at (4, 0) will lie at (4+x, 0+y)

Similarly:-

Now the vertex is shifted to (1,1,1)

So,

We can get the coordinates by shifting one unit in each coordinate :-

The coordinates become :-

(1,1,1)

(4,1,1)

(1,-2,1)

(1,1,-2)

(4,-2,1)

(1,-2,-2)

(4,1,-2)

(4,-2,-2)

Answer 2

Answer:

I don't know but you can search on