Question

$\huge\star\underline\mathrm\purple{Question}$
Kunal Kunal paint ka cubical water tank with lid for his house, with each outer edge 1.5m long. He gets the outer surface of the tank excluding the base covered with square tiles of side 25 cm. find how much he would spend for the tiles, if the cost of the tiles is Rs540 per dozen​

Answer 1

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Kunal paint ka cubical water tank with lid for his house, with each outer edge 1.5m long. He gets the outer surface of the tank excluding the base covered with square tiles of side 25 cm. find how much he would spend for the tiles, if the cost of the tiles is Rs540 per dozen.

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The length of the each side of water tank = 1.5m = 150cm

As it is given that base is not covered with tiles so, five sides of the tank are covered with tiles.

Therefore,

Surface area of water tank = 5a² = 5(150)² = 112500 cm²

Side of tile = 25 cm

Area of tile = 25² = 625 cm²

Number of tiles to cover five sides of the tank = 112500/625 = 180

Now,

Cost of one dozen tiles = Rs.540

Hence, total cost of 180 = 540/12

× 180 = Rs.8100 (Answer).

Explanation:

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Answer 2

$\huge\underline\bold \red {♡QUESTION♡}$

Kunal paint ka cubical water tank with lid for his house, with each outer edge 1.5m long. He gets the outer surface of the tank excluding the base covered with square tiles of side 25 cm. find how much he would spend for the tiles, if the cost of the tiles is Rs540 per dozen.

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The length of the each side of water tank = 1.5m = 150cm

As it is given that base is not covered with tiles so, five sides of the tank are covered with tiles.

Therefore,

Surface area of water tank = 5a² = 5(150)² = 112500 cm²

Side of tile = 25 cm

Area of tile = 25² = 625 cm²

Number of tiles to cover five sides of the tank = 112500/625 = 180

Now,

Cost of one dozen tiles = Rs.540

Hence, total cost of 180 = 540/12× 180 = Rs.8100 (Answer).

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