if E= 6 i^ +3j^ + 4k^ , calculate the electric flux through a surface of area 20 units in Y-Z plane
Answers
Answered by
3
Electric Flux = E.A
Here, E = 6i^ +3j^ + 4k^
A = 20i^
So, Electric flux = 6(20)+ 3(0) + 4(0)
= 120 Vm
Answered by
1
E
=10
i
^
+3
j
^
+4
k
^
Since, we have surface area of unit 10 lying in Y
2
plane.\perp^rto[laneY_z$$]
Hence, the area vector $$
S
=10
i
^
We know that
flux (ϕ) is given as
ϕ=∫
E
⋅
ds
ϕ=
E
⋅
S
=(10
i
^
+3
j
^
+4
k
^
)⋅(10
i
^
)
ϕ=100Nm²C^-1
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