Physics, asked by Anonymous, 3 months ago


\huge\star\underline{\mathtt\color{aqua}{⫷❥Q᭄} \mathfrak\color{yellow}{u~ }\mathfrak\color{blue}{Σ} \mathbb\color{purple}{ §} \mathtt\color{orange}{T} \mathbb\color{red}{iOn⫸}}\star\:⋆


if E= 6 i^ +3j^ + 4k^ , calculate the electric flux through a surface of area 20 units in Y-Z plane​

Answers

Answered by FehlingSolution
3

Electric Flux = E.A

Here, E = 6i^ +3j^ + 4k^

A = 20i^

So, Electric flux = 6(20)+ 3(0) + 4(0)

= 120 Vm

Answered by dasmirasree6
1

E

=10

i

^

+3

j

^

+4

k

^

Since, we have surface area of unit 10 lying in Y

2

plane.\perp^rto[laneY_z$$]

Hence, the area vector $$

S

=10

i

^

We know that

flux (ϕ) is given as

ϕ=∫

E

ds

ϕ=

E

S

=(10

i

^

+3

j

^

+4

k

^

)⋅(10

i

^

)

ϕ=100Nm²C^-1

Similar questions