Question

$\huge\star{\underline{\underline{\tt{\orange{Class\:11 \\ JEE Advanced}}}}}\star$

If $\large\sum\limits_{n=1}^{2013}\tan\big({\frac{\theta}{{2}^{n}}}\big)\sec\big({\frac{\theta}{{2}^{n-1}}}\big) = \tan\big({\frac{\theta}{{2}^{a}}}\big) - \tan\big({\frac{\theta}{{2}^{b}}}\big)$ then a+b equals to?

A]2014

B]2012

C]2013

D]2014

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Answer 1

refer to this attachment

so,option(c) 2013 should be correct.

hope it helps uhh !

great thanks !❤

Answer 2

hEy !!

ƭσµɠɦ ƭɦα ყɾɾ xD

Refers to the attachment ❤