Question

$\huge \text{Question:}$
22.4 litres of a gas weighs 70 g at S.T.P. Calculate the weight of the gas if it occupies a volume of 20 litres at 27°C and 700 mm Hg of pressure.

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Answer 1

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Answer 2

By gas law:

PV= nRT, where P is pressure of the gas at the temperature T and R is a gas constant and n is the substance of gas in moles.

Put values in the equation For STP and The given temprature and pressure situations.

760d)(22.4)=(70/200.59)R(273.15) (1)

(700d)(20)=(x/200.59)R(273.15+27) (2)

(1)/(2) eleminates R and reduces To:

760*22.4/(700*20) = (70/x)(273.15)/290.15

x=70*273.15*700*20/(290.15*760*22.4)

= 54.17 g

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