Question

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ғɪɴᴅ ᴛʜᴇ ϙᴜᴀᴅʀᴀᴛɪᴄ ᴘᴏʟʏɴᴏᴍɪᴀʟ ᴡʜᴏsᴇ sᴜᴍ ᴏғ ᴛʜᴇ ᴢᴇʀᴏᴇs ᴀʀᴇ 21/8 ᴀɴᴅ 5/16 ʀᴇsᴘᴇᴄᴛɪᴠᴇʟʏ.

sᴘᴀᴍ ᴋʀɴᴀ ᴍᴀɴᴀ ʜᴀɪ ❌​

Answer 1

Question

ғɪɴᴅ ᴛʜᴇ ϙᴜᴀᴅʀᴀᴛɪᴄ ᴘᴏʟʏɴᴏᴍɪᴀʟ ᴡʜᴏsᴇ sᴜᴍ ᴏғ ᴛʜᴇ ᴢᴇʀᴏᴇs ᴀʀᴇ 21/8 ᴀɴᴅ product of zeros is 5/16 ʀᴇsᴘᴇᴄᴛɪᴠᴇʟʏ.

Solution

Given :-

• Sum of zeroes = 21/8
• product of zeros = 5/16

Find :-

• Quadratic equation

Explanation

Let,

• First zeros of quadratic equations = p
• Second zeroes of quadratic equations = q

Since,

• (p + q ) = 21/8 _______(1)
• p.q = 5/16 ___________(2)

Formula of Quadratic Equation.

$\boxed{\underline{\tt{\red{\:x^2\:-\:x(p+q)\:+\:(p.q)\:=\:0}}}}$

So, Keep all above Values,

==> x² - (21/8/x + (5/16) = 0

Take L.C.M. from both

==> 16x² - 42x + 5 = 0

Hence

• Quadratic equations will be (16x² - 42x + 5 = 0).

_____________________

Answer 2

Step-by-step explanation:

$Given :-</p><p></p><p>Sum of zeroes = 21/8</p><p></p><p>product of zeros = 5/16</p><p></p><p>Find :-</p><p></p><p>Quadratic equation</p><p></p><p>Explanation</p><p></p><p>Let,</p><p></p><p>First zeros of quadratic equations = p</p><p></p><p>Second zeroes of quadratic equations = q</p><p></p><p>Since,</p><p></p><p>(p + q ) = 21/8 _______(1)</p><p></p><p>p.q = 5/16 ___________(2)</p><p></p><p>Formula of Quadratic Equation.</p><p>\boxed{\underline{\tt{\red{\:x^2\:-\:x(p+q)\:+\:(p.q)\:=\:0}}}}x2−x(p+q)+(p.q)=0</p><p>So, Keep all above Values,</p><p>==> x² - (21/8/x + (5/16) = 0</p><p>Take L.C.M. from both</p><p>==> 16x² - 42x + 5 = 0</p><p></p><p>Hence</p><p></p><p>Quadratic equations will be (16x² - 42x + 5 = 0).</p><p></p><p>_____________________</p><p></p><p>$