Question

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→ Given that (k-7) is the H.C.F. of 56 and 104, find the value of k. ←

~Only for ItzNawaabzadi12*​

Answer 1

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HCF ( 56 , 104 ) = 0

K - 7 = 0

K = 7

Hence , value of k = 7 .

Answer 2

Answer:

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The Highest Common factor of 56 and 104 is 8

It is given that (k-7) is the HCF of 56 and 104

so, k-7 = 8

k = 8 + 7

k = 15

Therefore the value of k is 15

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