Math, asked by Aaravshith577, 1 month ago


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The following observations has been arranged in ascending order . If the median of the data is 27 , Find the value of x 13,19,20,25,x,x+2,33,34,35,36​



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Answers

Answered by itzshygirl08
0

Answer:

hence n=10

median =5th+6th/2 term

median =22+x/2=23

x=46-2

=24

if 32 is replaced by 23 then the observation will be

12, 14, 17, 20, 23, 24, 26, 36

now median=22+33/2=22.5

Answered by BrainlyFlash
17

Question :-

The following observations has been arranged in ascending order . If the median of the data is 27 , Find the value of x 13,19,20,25,x,x+2,33,34,35,36

Answer :-

Given :

  • Median of data = 27

Solution :

Number of terms n = 10 (even)

Since the number of terms is even.

  \sf \: median   =  \bigg \{\dfrac{  \big(\dfrac{n}{2}  \big)  ^{th}  +  \big( \dfrac{n}{2}  + 1  \big) ^{th} }{2}  \bigg \}

 \sf \leadsto median   =  \bigg \{\dfrac{  \big(\dfrac{10}{2}  \big)  ^{th}  +  \big( \dfrac{10}{2}  + 1  \big) ^{th} }{2}  \bigg \}

 \sf \leadsto median =  \dfrac{5 + 6}{2}

 \sf \leadsto \: median = 5.5th \: term

5.5th term lies between 5th and 6th term

 \therefore \sf \leadsto \dfrac{(x) + (x + 2)}{2}  = 27

 \leadsto \sf \: 2x + 2 = 54

 \leadsto \sf \: 2x  = 54 - 2

 \leadsto \sf \: x =  \dfrac{52}{2}

 {\boxed{ \red{ \dag \sf \: x =  26 \dag}}}

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