A circus tent is cylindrical to a height of 4 m and conical above it. If its diameter is 105 m and its slant height is 40 m. Find the total area of the canvas required ( in m² )
Answers
Answer:
The total area of the canvas required is d) 7920.
Step-by-step explanation:
Given :-
A circus tent is cylindrical to a height of 4 m and conical above it.
Its diameter is 105 m and its slant height is 40 m.
To find :-
The total area of the canvas required.
Solution :-
Formula used :
★{\boxed{\sf{CSA\:of\: cylinder=2\pi\:rh}}}
CSAofcylinder=2πrh
★ {\boxed{\sf{CSA\:of\:cone=\pi\:rl}}}
CSAofcone=πrl
In case of cylinder ,
Diameter = 105 m
Height (h)= 4 m
Then,
Radius(r) of the cylinder = 105/2 = 52.5 m.
CSA of the cylinder ,
= 2πrh
= [2× (22/7)× 52.5×4] m²
= 9240/7 m²
= 1320 m²
In case of conical part,
Radius of cylinder = Radius of cone
Radius (r)= 52.5 m
Slant height (l)= 40 m
CSA of conical part,
= πrl
= [(22/7) × 52.5 × 40 ] m²
= 46200/7 m²
= 6600 m²
Therefore,
Total area of the canvas required,
= CSA of cylinder + CSA of cone
= (1320 + 6600) m²
= 7920 m²
Therefore, the total area of the canvas required is 7920 m².
Answer:
- Total area of the canvas required = 14520m^2.
Given:
- Height of cylindrical tent is 4m.
- Diameter is 105m.
- Slant height is 40m.
To Find:
- Total area of the canvas required= ?
Solution:
For cylindrical
Diameter is 105m.
Let's convert in radius
As we know that,
Now put on formula
•radius = 105/2m
Now height is 4m for cone
Slant height = 40 × 2 = 80m
Total surface area of the tent is the sum of lateral surface area of cone and cylinder
= 2πrh + πrl
= 2 × 22/7 × 105/2 × 4 + 22/7 × 105/2 × 80
= 1320 + 13200
= 14520m^2.
Hence,total surface area is 14520 m^2.
Note:-
- R is radius here.
- h is height .
- π = 22/7
- l is length.
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