Question

$\huge\tt\blue{Question}$
Find the area of a triangle whose sides are AB=√18 cm, BC=5 cm, AC= 7cm tex]​

Answer 1

Answer:

are of the triangle = 10.5

Step-by-step explanation:

here we take the length of AB=a=square root of 18 cm

BC=b=5 cm and AC=c=7 cm

the area of the triangle S= (a+b+c)/2

=(root of 18+5+7)/2

S = 8.12 sqcm.