Question

$\huge\tt\colorbox{black}{\color{red}{Question}}$
The effective magnetic moment of Ni2+ is
(a) 0BM
(b) 4.5 BM
(c) 2.8 BM
(d) 1.73 BM​

Answer 1

Answer:-

2.8 BM [Option.c]

Explanation:-

Firstly, we have to calculate the number of unpaired electrons in Ni²⁺ .

• Atomic number of Nickel (Ni) = 28

Electronic configuration of Ni :-

= 1s²2s²2p⁶3s²3p⁶3d⁸4s²

= [Ar]3d⁸4s²

Ni²⁺ ion is formed when Ni loses 2 electrons.

So the electronic configuration of Ni²⁺ is :-

= [Ar]3d⁸

Hence, number of unpaired electrons in Ni²⁺ is 2.

Now, we know the formula :

μ = √n(n + 2)

Where:-

• μ is magnetic moment.

• n is the number of unpaired electrons.

=> μ = √2(2 + 2)

=> μ = √2(4)

=> μ = √8

=> μ = 2.8 BM

Thus, the effective magnetic moment of Ni²⁺ is 2.8 BM .