Question

$\huge \tt{Don't \: Spam}$​

Answer 1

Answer:

Length of two legs is 12 cm and 5 cm.

length of hypotenuse =

h² = p²+b²

h² = 12²+5² = 144+25 = 169

h = √169 = 13 cm

So perimeter = 12+5+13 = 30cm

Answer 2

Explanation:

Given a right triangle, given its two legs, 12 cm and 5 cm, what is the hypotenuse?

Using Pythagoreans' theorem: A^2+B^2=C^2; we can find the hypotenuse (C). Here we have A=12 and B=5.

Substituting and solving gives us (12)^2+(5)^2=C^2 and then we find C^2=144+25. which reduces to C^2=169 which equals C=13.

Therefore the hypotenuse of this right triangle is 13 cm.

So perimeter = 12+5+13

=30cm