Question

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factorise 3y²+3y-36

ɪ ʀᴇǫᴜᴇsᴛ ᴜ ɢᴜʏs ɴᴏᴛ ᴛᴏ❌sᴘᴀᴍ❌

ツ​

Answer 1

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32+3−36

3(2+−12)

[tex]3(2+−12)

3(2+4−3−12)

3(2+4−3−12)

3((+4)−3(+4))

3((+4)−3(+4))

3(−3)(+4)

Answer 2

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$Common \: factor \\ 3y²+3y−36 \\ 3(y²+y−12) \\ Use \: the \: sum-product \: pattern \\ 3(y²+y−12) \\ 3(y²+4y−3y−12) \\ Common \: factor \: from \: the two \: pairs \\ 3(y²+4y−3y−12) \\ 3(y(+4)−3(y+4)) \\ Rewrite \: in \: factored \: form \\ 3(y(y+4)−3(y+4)) \\ 3(y−3)(y+4)$

Hope this helps you ✌️✌️