The masses of two different bodies are 6000 kg and 24000 kg respectively. The distance between both the bodies is 3 km. Find the position where an object should be kept along the line joining the centres of both the bodies, such that the net gravitational force on the object is zero.
(Take G = 6.7 x 10-¹¹ N m² kg-²)
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Step-by-step explanation:
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F=R2Gm1m2
In the above formula,
G=6.67×10−11,m1=800kgandR=10m
⇒6.67×10−7=1006.67×10−11×800×m2
⇒m2=1250kg
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HERE IS UR ANSWER
F=R2Gm1m2
In the above formula,
G=6.67×10−11,m1=800kgandR=10m
⇒6.67×10−7=1006.67×10−11×800×m2
⇒m2=1250kg
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