Math, asked by kamalhajare543, 1 month ago


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If (Sec A + tan A ) (SecB + tanB) (Sec C + tanC) = (Sec A -tanA) (Sec B - tan B) (Sec C - tan C ) . Prove that each of the side is equal to ±1 .

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Answers

Answered by soumili0922b
1

Answer:

{\huge{\tt{\orange{\fcolorbox{ref}{blue}{\underline{QUESTION :}}}}}} \\ \ \textless \ br /\ \textgreater \

If (Sec A + tan A ) (SecB + tanB) (Sec C + tanC) = (Sec A -tanA) (Sec B - tan B) (Sec C - tan C ) . Prove that each of the side is equal to ±1 .

• Best Of Luck !!

• Spammers Stay Away !!

• Quality answer mark as Brainliest !!

{\huge{\tt{\orange{\fcolorbox{ref}{blue}{\underline{QUESTION :}}}}}} \\ \ \textless \ br /\ \textgreater \

If (Sec A + tan A ) (SecB + tanB) (Sec C + tanC) = (Sec A -tanA) (Sec B - tan B) (Sec C - tan C ) . Prove that each of the side is equal to ±1 .

• Best Of Luck !!

• Spammers Stay Away !!

• Quality answer mark as Brainliest !!

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