Question

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The longest wavelength doublet absorption transition is observed at 589 to 58.6 nm. Calculate the frequency of each transition and energy difference between two excited stated.

Tʜɪꜱ Qᴜᴇꜱᴛɪᴏɴ Iꜱ Oɴʟʏ Fᴏʀ Mᴏᴅᴇʀᴀᴛᴏʀꜱ, Bʀᴀɪɴʟʏ Sᴛᴀʀꜱ Aɴᴅ Oᴛʜᴇʀ Bᴇꜱᴛ Uꜱᴇʀꜱ

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Answer 1

Answer:

2 - 89 286 PM and then divide in maths

Answer 2

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Step-by-step explanation:

We know

• frequency = speed of light /wavelength

For wavelength ( λ₁ ) = 589 nm

frequency (v₁ ) = 3 × 10^8/589 × 10^-9

= 5.093 × 10¹⁴ Hz

For wavelength ( λ₂ ) = 589.6 nm

frequency ( v₂ ) = 3 × 10^8/589.6 × 10^-9

=5.088 × 10¹⁴ Hz

now, energy difference (∆E) = E₁ - E₂

∆E = E₁ - E₂ = hv₁ - hv₁

= h(v₁ - v₂)

= 6.626 × 10^-34 × ( 5.093 - 5.088) × 10¹⁴

= 6.626 × 0.005 × 10^(-34 + 14) J

= 3.31 × 10^-22 J