Fill in the blanks
• in India the practice of bonded labour restricts _____ freedom
• ______ give the term unity in diversity of India
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Answers
Answer:
QUESTION★᭄
★᭄Fill in the blanks•
- in India the practice of bonded labour restricts _____ freedom
- ______ give the term unity in diversity of India
Answer ➜
- Legal recitation
- Unity in diversity
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Answer:
Given: The edges of a triangluar Board are 6 cm, 8 cm and 10 cm. & The cost of painting it at the rate of Rs 5 per cm².
Need to find: The Cost of painting?
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
❍ Let's say, that the sides of triangle be x, y and z are 6 cm, 8 cm & 10 cm respectively.
⌑ We'll use Heron's formula to find out the area of the given triangular Board. First we'll calculate semi – perimeter of the triangle —
» Semi - perimeter is Gievn by sum of all sides of triangle —
\begin{gathered}:\implies\sf S = \Bigg\{\dfrac{x + y + z}{2}\Bigg\}\\\\\\\end{gathered}
:⟹S={
2
x+y+z
}
\begin{gathered}:\implies\sf S = \Bigg\{\dfrac{6 + 8 + 10}{2}\Bigg\}\\\\\\\end{gathered}
:⟹S={
2
6+8+10
}
\begin{gathered}:\implies\sf S = \cancel\dfrac{24}{2}\\\\\\\end{gathered}
:⟹S=
2
24
\begin{gathered}:\implies{\boxed{\pmb{\frak{S = 12\;cm}}}}\\\\\end{gathered}
:⟹
S=12cm
S=12cm
\begin{gathered}\therefore{\underline{\textsf{Hence, Semi-perimeter of the triangle is \textbf{12 cm.}}}}\\\end{gathered}
∴
Hence, Semi-perimeter of the triangle is 12 cm.
⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
✇ Now, Calculating area of the triangle —
⠀
\begin{gathered}\star\;\underline{\pmb{\boxed{\sf{Area_{\:(triangle)} = \sqrt{s\Big(s - a\Big)\Big(s - b\Big)\Big(s - c\Big)}}}}}\\\\\end{gathered}
⋆
Area
(triangle)
=
s(s−a)(s−b)(s−c)
Area
(triangle)
=
s(s−a)(s−b)(s−c)
\begin{gathered}:\implies\sf Area_{\:(triangle)} = \sqrt{12\Big(12 - 6\Big)\Big(12 - 8\Big)\Big(12 - 10\Big)} \\\\\\\end{gathered}
:⟹Area
(triangle)
=
12(12−6)(12−8)(12−10)
\begin{gathered}:\implies\sf Area_{\:(triangle)} = \sqrt{12\times 6 \times 4 \times 2}\\\\\\\end{gathered}
:⟹Area
(triangle)
=
12×6×4×2
\begin{gathered}:\implies\sf Area_{\;(triangle)} = \sqrt{576}\\\\\\\end{gathered}
:⟹Area
(triangle)
=
576
\begin{gathered}:\implies\underline{\boxed{\pmb{\frak{Area_{\:(triangle)} = 24\;cm^2}}}}\;\bigstar\\\\\end{gathered}
:⟹
Area
(triangle)
=24cm
2
Area
(triangle)
=24cm
2
★
\begin{gathered}\therefore{\underline{\sf{Hence,\; Area\; of \;the\; triangle \;is \;{\pmb{\sf{24\;cm^2}}}.}}}\\\end{gathered}
∴
Hence,Areaofthetriangleis
24cm
2
24cm
2
.
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» Now, we've to find out the cost of painting the board at rupees 5 per cm². So, Let's Solve :
⠀
\begin{gathered}\longrightarrow{ \pmb{\mathbb{ COST = RATE \times AREA }}}\\\\\end{gathered}
⟶
COST=RATE×AREA
COST=RATE×AREA
\begin{gathered}\longrightarrow\sf Cost = 5 \times 24 \\\\\end{gathered}
⟶Cost=5×24
\begin{gathered}\longrightarrow\underline{\boxed{\pmb{\frak{Cost = 120}}}}\;\bigstar\\\\\end{gathered}
⟶
Cost=120
Cost=120
★
\therefore{\underline{\sf{Hence,\; the \;Cost\; of\; painting \;is~ {\pmb{\sf{Option~ c)~120~ rs}}}.}}}∴
Hence,theCostofpaintingis
Option c) 120 rs
Option c) 120 rs.