The angle of elevation of the top of a tower from two points distant s and t from its foot are complementary. Prove that the height of the tower is √st.
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Let complementary angles be
α and 90−α
tan α = h/s
tan (90−α) = cot α = h/t
multiply (i) and (ii)
tan α. cot α= h/s . h/t
h²/ts = 1
h= √ st
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