Question

$\huge\tt{Question:-}$
A car moving with a speed of 10m/s from rest in 2 sec. Find its accleration.

answer needed with solution​

Answer 1

Given,

r=2m

v=10m/s

at=10m/s^2

Centripetal acceleration,

ac= v^2/r

ac=10×10/2

=50m//s^2

acceleration, a= ac^2+at^2

a= 50^2+10^2 m/s^2

a=10/26m/s^2

The correct option is B.

hope it's helpful

sorry I can't write properly bcuz of some issues

Answer 2

Explanation:

Now let's see what is given in the question.

time=?

Initial velocity=10m/s

Final velocity=0m/s

Acceleration=-2m/s

To find time we will use the formula of acceleration,

a=v-u/t

-2=0-10/t

-2t=-10

-t=-10/2

t=5

Now we have to find stopping distance.

We will solve this by 2nd kinematical equation of motion.

S=ut+1/2at^2

S=(10×5)+1/2×2×(5^2)

S=50+1×25

S=50+25

S=75 m

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Nd yes Happy birthday friend