Question

$\huge\tt{Question:}$

Find the amount received after depositing Rs 800 for a period of 3 years at the rate of 12% per annum.

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Answer 1

$\bf\huge\mathfrak\red{\underline{Your\:Answer}}$

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Principal = Rs 800

Time = 3years

Rate of interest = 12% p.a.

Simple Interest = Prt/100

= Rs ( 800×3×12 /100 )

= Rs 288

Therefore, Amount ( in case of SI ) = Principal + Interest = Rs 800 + Rs 288 = Rs 1088

Ans => Rs 1088

Now, Amount (in case of compound interest)

= P( 1+r/100 )^t

= Rs [ 800 ( 1 + 12/100 )³

= Rs 1123.94 (approx)

Ans => Rs 1123.94 (approx)

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Hope this helps uh!

Be brainly ♠️

Answer 2

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

$\tt\huge{Finding\:Simple\:Interest:-}$

Formula :-

$\huge\tt{\boxed{\dfrac{PRT}{100}}}$

Putting in the values,

$\leadsto\tt{\dfrac{800\times 12\times 3}{100}}$

$\leadsto\tt{\dfrac{28,800}{100}}$

$\leadsto\huge\tt{\boxed{\pink{Rs.\:288}}}$

Final Amount = Principal + SI

$\leadsto\tt{800+288}$

$\leadsto\huge\tt{\boxed{\pink{Rs.\:1088}}}$

$\tt\huge{Finding\:compound\:Interest:-}$

Formula :-

$\huge\tt{\boxed{P{(1+\dfrac{r}{100})}^{t}}}$

Putting in the values,

$\leadsto\tt{800{(1+\dfrac{12}{100})}^{3}}$

$\leadsto\tt{800\times1.404928}$

$\leadsto\huge\tt{\boxed{\pink{Rs.\:1,123.9424}}}$

$\rule{200}5$