Question

$\huge {\tt{Question}}$
If the value of $\sf{tan~\alpha={\dfrac{5}{2}}}$ , find the value of cot θ if $\sf{\alpha+ \theta = 90°} .$ ​

Answer 1

$\huge {\tt{Answer}}$

From the eqn. $\sf{\alpha + \theta =90°}$ , we have

$\sf{\theta = 90° - \alpha} \\\\ \sf {cot \theta= ~cot(90°-\alpha) = tan~\alpha} \\\\ \sf{ cot\theta=\dfrac{5}{2}}$

Answer 2

Hope my answer helps you....