Question

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Two resistances when connected in parallel give resultant value of 2 ohm, when connected in series the value become 9ohm. calculate the value of each resistor.

$ᴛʜᴀɴᴋ \: \: ᴍʏ \: \: ᴀɴsᴡᴇʀs❥︎$
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Answer 1

Answer:

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Explanation:

Let the two resistances be R1 and R2.

If connected in series, then

9 = R1 + R2

R1 = 9 - R2

If connected in parallel, then

1/2 = 1/R1 + 1/R2

From above equations we get that

1/2 = (R1 + R2)/R1R2

1/2 = 9/(9 - R2) R2

9R2 - R22 = 18

R22 - 9R2 + 18 = 0

(R2 - 6) (R2 - 3) = 0

R2 = 6,3

So if R2 = 6ohms, then R1 = 9 - 6 = 3 ohms.

If R2 = 3ohms, then R1 = 9 - 3 = 6ohms.

Answer 2

Answer:

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its Khushi

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