Question

$\huge \tt \red{Question:-}$

If alpha and beta are the zeros of the polynomial f (x) = 16x^2 + 4x - 5, then 1/alpha + 1/beta =?

#Seenu bhai ​

Answer 1

Answer:

If α, β are the zeros of the quadratic polynomial f(x)=16x2+4x−5, then,

(α+β)=a−b=−164=−41,  αβ=ac=16−5

Now, α1+β1 =αβα+β

=16−5−41 =4×516

=54

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

If α, β are the zeros of the quadratic polynomial f(x)=16x

2

+4x−5, then,

(α+β)=

a

−b

=−

16

4

=−

4

1

, αβ=

a

c

=

16

−5

Now,

α

1

+

β

1

=

αβ

α+β

=

16

−5

−

4

1

=

4×5

16

=

5

4