Question

$\huge \underbrace \bold \blue {↓Question↓}$

A ᴄᴏɴᴠᴇx ᴍɪʀʀᴏʀ ᴜsᴇᴅ ғᴏʀ ʀᴇᴀʀ ᴠɪᴇᴡ ᴏɴ ᴀɴ ᴀᴜᴛᴏᴍᴏʙɪʟᴇ ʜᴀs ᴀ ʀᴀᴅɪᴜs ᴏғ ᴄᴜʀᴠᴀᴛᴜʀᴇ ᴏғ 3.00ᴍ. Iғ ᴀ ʙᴜs ɪs ʟᴏᴄᴀᴛᴇᴅ ᴀᴛ 5.00ᴍ ғʀᴏᴍ ᴛʜɪs ᴍɪʀʀᴏʀ. Fɪɴᴅ ᴛʜᴇ ᴘᴏsɪᴛɪᴏɴ, ɴᴀᴛᴜʀᴇ ᴀɴᴅ sɪᴢᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ.

❌ɴᴏ ᴄᴏᴘʏ
❌ɴᴏ sᴘᴀᴍ

Mɪss ɪᴢᴢᴀᴛᴅᴀᴀʀ❤️࿐​

Answer 1

Answer:

ʜᴏᴘᴇ ɪᴛᴢ ʜᴇʟᴘғᴜʟ

ɪɴʙᴏx me(❁´◡`❁)

Answer 2

ǫᴜᴇsᴛɪᴏɴ-:

A ᴄᴏɴᴠᴇx ᴍɪʀʀᴏʀ ᴜsᴇᴅ ғᴏʀ ʀᴇᴀʀ ᴠɪᴇᴡ ᴏɴ ᴀɴ ᴀᴜᴛᴏᴍᴏʙɪʟᴇ ʜᴀs ᴀ ʀᴀᴅɪᴜs ᴏғ ᴄᴜʀᴠᴀᴛᴜʀᴇ ᴏғ 3.00ᴍ. Iғ ᴀ ʙᴜs ɪs ʟᴏᴄᴀᴛᴇᴅ ᴀᴛ 5.00ᴍ ғʀᴏᴍ ᴛʜɪs ᴍɪʀʀᴏʀ. Fɪɴᴅ ᴛʜᴇ ᴘᴏsɪᴛɪᴏɴ, ɴᴀᴛᴜʀᴇ ᴀɴᴅ sɪᴢᴇ ᴏғ ᴛʜᴇ ɪᴍᴀɢᴇ.

sᴏʟᴜᴛɪᴏɴ-:

$\green\implies$ $\sf\frac{2}{R}$ = $\sf\frac{1}{u}$ + $\sf\frac{1}{v}$

$\green\implies$ $\sf\frac{2}{3}$ = $\sf\frac{1}{-5}$ + $\sf\frac{1}{v}$

$\sf\frac{1}{v}$ = $\sf{0.866}$⇛v = $\sf{1.15cm}$

ᴍᴀɢɴɪғɪᴄᴀᴛɪᴏɴ-:

$\green\implies$-$\sf\frac{v}{u}$ = -$\sf\frac{1.15}{-5}$ = $\sf{0.23}$

ʙᴇ ʙʀᴀɪɴʟʏツ