Question

$\huge\underbrace\mathfrak\red{Ouestion}!!!$
Prove that 3=4

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Answer 1

Answer:

superb question

Explanation:

let's consider

0= 0

so

we have

15 -15=20-20

taking 3 common in Lhs and 4 common in rhs

3(5-5)=4(5-5)

so we cancel 5-5

we have 3=4

pls mark as brainlist

hope it helps you

Answer 2

Mathematical Fallacies: Can we prove that 1=2 or 2=3 or 3=4 and so on?

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Updated 6 years ago

Mathematical Fallacies: Can we prove that 1=2 or 2=3 or 3=4 and so on?

First, let's assume the rules of arithmetic[1] apply. We can reduce each of your cases to asking whether we can prove 1=0 .

What happens if we live in a universe where 1=0 ? Well, let x be any number at all and assume that 1=0 , then

From this it follows that x=0 . So, if 1=0 and we live in a world where the rules of arithmetic (as usually defined) apply then every number equals 0 .

What this means is that if you want to be logically consistent then you can only believe one of the following:

1≠0

There is only one number, 0 .

Of course, if you decide to give up logical consistency then you can "prove" anything you want, including that 1≠0 and 1=0 simultaneously.

A more mathy way of saying this is that if (K,+,⋅) is a ring whose additive and multiplicative identities are 0 and 1 , respectively, then K={0} if and only if 1=0 .

[1]: We could be precise about what we mean by "rules of arithmetic," if we wanted. It would include familiar rules like

There exists a number (denoted 1 ) such that 1⋅x=x⋅1=x for any number x

For any two numbers x,y , we have x+y=y+x

For any two numbers x,y , we have x⋅y=y⋅x

There would be nine such rules in total.

Hope it will help.