Math, asked by anshikadwivedi141, 1 month ago


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Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.



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Answered by prajwalchaudhari
0

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Answered by Anonymous
1

QUESTION :

Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.

ANSWER :

=> LCM OF 8,15 AND 21 => 3×2×2×2×5×7= 840

SO, NOW LET 110000 DIVIDED BY 840

SO THE REMAINDER WILL BE 800.

NUMBER LESS THAN 110000 and nearest to 110000 that is divisible by 840 is 110000- 800 = 109200

=> so the required number is 109200

HOPE IT'S HELPFUL TO YOU.

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