Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.
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QUESTION :
Determine the number nearest to 110000 but greater than 100000 which is exactly divisible by each of 8,15 and 21.
ANSWER :
=> LCM OF 8,15 AND 21 => 3×2×2×2×5×7= 840
SO, NOW LET 110000 DIVIDED BY 840
SO THE REMAINDER WILL BE 800.
NUMBER LESS THAN 110000 and nearest to 110000 that is divisible by 840 is 110000- 800 = 109200
=> so the required number is 109200
HOPE IT'S HELPFUL TO YOU.
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