Question

$\huge\underline\bold\red{♡QueStiOn♡}$


The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs.160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs.300. Represent the situation algebraically.
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Answer 1

let the Apple be x and grapes be y

then 2x+y= 160.............EQ.1

and,

after a month

4x+2y= 300.................EQ.2

Answer 2

Answer:

Let the cost of 1 kg apples be 'x'

The cost of 1 kg grapes be 'y'

Therefore, cost of 2 kg apples = 2x

and cost of 1 kg grapes = y

Total cost of 2 kg apples and 1 kg grapes is Rs. 160.

Algebrically, 2x + y = 160 ——————Eq. (1)

After a month,

Cost of 4 kg apples = 4x

and Cost of 2 kg grapes = 2y

Now, the total cost of 4 kg apples and 2 kg grapes is Rs. 300.

Algebrically, 4x + 2y = 300 ——————Eq.(2)

Hope you got your answer

Thank you